Tags: Collection , List

Collections.disjoint(Collection<?> c1, Collection<?> c2)
Returns true if the two specified collections have no elements in common.

Source Code

import java.util.ArrayList;
import java.util.Collections;
import java.util.List;

/**
 * @author javaQuery
 */
public class DisjointExample {

    public static void main(String[] args) {
        /* Create list of String */
        List<String> listString = new ArrayList<String>();
        /* Add elements in listString */
        listString.add("a");
        listString.add("b");
        listString.add("c");

        /* Create list of String */
        List<String> listStringSecond = new ArrayList<String>();
        /* Add elements in listString */
        listStringSecond.add("x");
        listStringSecond.add("y");
        listStringSecond.add("z");

        System.out.println("Initial List 1: " + listString);
        System.out.println("Initial List 2: " + listStringSecond);
        System.out.println("------------------------");
        System.out.println("Disjoint: " + Collections.disjoint(listString, listStringSecond));

        /* Add element available in listString */
        listStringSecond.add("a");
        System.out.println("------------------------");
        System.out.println("List 2 after add(\"a\"): " + listStringSecond);
        System.out.println("Disjoint after add(\"a\"): " + Collections.disjoint(listString, listStringSecond));
    }
}

Output

Initial List 1: [a, b, c]
Initial List 2: [x, y, z]
------------------------
Disjoint: true
------------------------
List 2 after add("a"): [x, y, z, a]
Disjoint after add("a"): false

Tags: Collection , List